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3b^2-21b+22=0
a = 3; b = -21; c = +22;
Δ = b2-4ac
Δ = -212-4·3·22
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{177}}{2*3}=\frac{21-\sqrt{177}}{6} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{177}}{2*3}=\frac{21+\sqrt{177}}{6} $
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